SOLUTION: Joe saved a number of nickels,dimes, and quarters. He had 3 more dimes than nickels. He also had 6 more than twice as many quarters as dimes. He had a total of 5.05. How many of ea

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Joe saved a number of nickels,dimes, and quarters. He had 3 more dimes than nickels. He also had 6 more than twice as many quarters as dimes. He had a total of 5.05. How many of ea      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 684302: Joe saved a number of nickels,dimes, and quarters. He had 3 more dimes than nickels. He also had 6 more than twice as many quarters as dimes. He had a total of 5.05. How many of each coin did he have
I tried this and doesn't make sense
nickles=n
dimes=n+3
quarters=2(n+3)+6
n+n+3+2(n+3)+6=5.05
.05n+.10n+.3+.50n+3=5.05


.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
dimes=n%2B3
quarters=2%28n%2B3%29%2B6
n%2Bn%2B3%2B2%28n%2B3%29%2B6=5.05
or in cents
+25q+%2B+10d+%2B+5n+=+505+ ( in cents )
---------------------------
plug in +q+=+2%28n%2B3%29%2B6 and +d+=+n%2B3+ and solve for n

+25%282%28n%2B3%29%2B6%29+%2B+10%28n%2B3%29%2B+5n+=+505+

+25%282n%2B6%2B6%29+%2B+10%28n%2B3%29%2B+5n+=+505+
+25%282n%2B12%29+%2B+10%28n%2B3%29%2B+5n+=+505+
+50n%2B300+%2B+10n%2B30%2B+5n+=+505+
+65n%2B330+=+505+
+65n+=+505+-330
+65n+=+175
n=2.6923076923076923076923076923077.......this and doesn't make sense, n should be whole number

possible solution:
n=3
d=4
q=18
but it doesn't match given data