SOLUTION: I rode my bike 30 miles. If I had increased my average speed by 3 mph, I would have decreased my travel time by 20 minutes. How many miles per hour was my original speed? I trie

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Question 684235: I rode my bike 30 miles. If I had increased my average speed by 3 mph, I would have decreased my travel time by 20 minutes. How many miles per hour was my original speed?
I tried to use d= r* t so 3x=30? I don't know what else to do

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
There are 2 equations. One is for the actual bike riding
the other is the option with higher speed.
Let +s+ = original speed in mi/hr
Let +t+ = original time in hrs
given:
(1) +30+=+s%2At+
(2) +30+=+%28+s+%2B+3+%29%2A%28+t+-+1%2F3+%29+
( note that 20 min is 1/3 hr )
---------------------------
(2) +30+=+s%2At+%2B+3t+-+%281%2F3%29%2As+-+1+
and
(1) +t+=+30%2Fs+
Substitute (1) into (2)
( note also that +s%2At+=+30+ )
(2) +30+=+30+%2B+3%2A%2830%2Fs%29+-+%281%2F3%29%2As+-+1+
Subtract +30+ from both sides, then add +1+ to both sides
(2) +90%2Fs+-+%281%2F3%29%2As+=+1+
Multiply both sides by +3s+
(2) +270+-+s%5E2+=+3s+
(2) +s%5E2+%2B+3s+=+270+
Complete the square:
(2) +s%5E2+%2B+3s+%2B+%283%2F2%29%5E2+=+270+%2B+%283%2F2%29%5E2+
(2) +s%5E2+%2B+3s+%2B+9%2F4+=+270+%2B+9%2F4+
(2) +%28+s+%2B+3%2F2+%29%5E2+=++1080%2F4+%2B+9%2F4+
(2) +%28+s+%2B+3%2F2+%29%5E2+=+1089+%2F+4+
Take the square root of both sides ( ignore the negative square root )
(2) +s+%2B+3%2F2+=+33%2F2+
(2) +s+=+30%2F2+
(2) +s+=+15+
Your original speed was 15 mi/hr
check:
(1) +30+=+s%2At+
(1) +30+=+15%2At+
(1) +t+=+2+
and
(2) +30+=+%28+s+%2B+3+%29%2A%28+t+-+1%2F3+%29+
(2) +30+=+%28+15+%2B+3+%29%2A%28+t+-+1%2F3+%29+
(2) +30+=+18%2A%28+t+-+1%2F3+%29+
(2) +30+=+18t+-+6+
(2) +18t+=+36+
(2) +t+=+2+
OK