SOLUTION: a chemist has one solution that is 25% acid and a second one that is 50% acid. how many liters of each should be mixed to get 10 liters of a solution that is 40% acid?
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Question 684100: a chemist has one solution that is 25% acid and a second one that is 50% acid. how many liters of each should be mixed to get 10 liters of a solution that is 40% acid? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a chemist has one solution that is 25% acid and a second one that is 50% acid.
how many liters of each should be mixed to get 10 liters of a solution that is 40% acid?
:
Let x = amt of 50% acid
the resulting amt is to be 10 liters, therefore
(10-x) = amt of 25% acid
:
A typical mixture equation
:
.50x + .25(10-x) = .40(10)
.50x + 2.5 - .25x = 4
.50x - .25x = 4 - 2.5
.25x = 1.5
x = 1.5/.25
x = 6 liters of 50% solution
and
10 - 6 = 4 liters of 25% solution
