SOLUTION: Find the equation of the line passing through the given point and perpendicular to the equation of the line. (-2,3) ; 5x-4y-6=0

Algebra ->  Equations -> SOLUTION: Find the equation of the line passing through the given point and perpendicular to the equation of the line. (-2,3) ; 5x-4y-6=0      Log On


   

Question 684046: Find the equation of the line passing through the given point and perpendicular to the equation of the line. (-2,3) ; 5x-4y-6=0
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Start with 5x-4y-6=0
5x-6 = 4y
y = %285%2F4%29x+-+6%2F4
has a slope of 5%2F4
A perpendicular line will have a negative inverse/reciprocal slope of -4%2F5
...
Use the slope and the point (-2, 3) in the point-slope formula
y - 3 = -4%2F5(x--2)
y - 3 = -4%2F5(x+2)
y - 3 = %28-4%2F5%29x+-+%284%2F5%29%282%29
y - 3 = %28-4%2F5%29x+-+8%2F5
y = %28-4%2F5%29x+-+8%2F5+%2B+3
y = %28-4%2F5%29x+-+8%2F5+%2B+3%285%2F5%29
y = %28-4%2F5%29x+-+8%2F5+%2B+15%2F5
...
highlight_green%28y=%28-4%2F5%29x%2B%287%2F5%29%29
.....................
Have more questions?
Email: HomeworkHelpers@readingboosters.com
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.