SOLUTION: Solve for t 10^(7t) = 18^(2t-5)
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Question 683960
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Solve for t
10^(7t) = 18^(2t-5)
Answer by
lwsshak3(11628)
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Solve for t
10^(7t) = 18^(2t-5)
7tlog10=(2t-5)log18
7t/2t-5=log18/log10≈1.2553
7t=1.2553(2t-5)=2.5105t-6.2764
7t-2.5105t=-6.2764
4.4894t=-6.2764
t≈-6.2764/4.4894
t≈-1.3980