SOLUTION: ten years ago,a father's age was three times the age of his son and ten years later,the father's age will be twice the age of his son.find their present ages.

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Question 683593: ten years ago,a father's age was three times the age of his son and ten years later,the father's age will be twice the age of his son.find their present ages.
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
and ten years later,the father's age will be twice the age of his son.find their present ages

>>...ten years ago, a father's age was three times the age of his son...<< 

That says

%28matrix%284%2C1%2C%0D%0A%0D%0A%22Father%27s%22%2C+present%2C+%22age%2C%22%2C+F%29%29 - %28matrix%282%2C1%2C%0D%0A%0D%0Aten%2Cyears%29%29 = 3×

>>...ten years later,the father's age will be twice the age of his son...<< 

That says

%28matrix%284%2C1%2C%0D%0A%0D%0A%22Father%27s%22%2C+present%2C+%22age%2C%22%2C+F%29%29 + %28matrix%282%2C1%2C%0D%0A%0D%0Aten%2Cyears%29%29 = 2×

Now write the two equations in F and S, use substitution
and find their ages.

I won't tell you the answers, but I'll tell you that when you
get the answers if you add their ages, you'll get 100.

Edwin