SOLUTION: Please help me solve this question
Evaluate: {{{8^(2(x+2))= 16^(x-2)}}}
I have started it but I'm not sure if I'm doing it right or how to continue.This is what I have:
log8^
Algebra ->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: Please help me solve this question
Evaluate: {{{8^(2(x+2))= 16^(x-2)}}}
I have started it but I'm not sure if I'm doing it right or how to continue.This is what I have:
log8^
Log On
Question 683281: Please help me solve this question
Evaluate:
I have started it but I'm not sure if I'm doing it right or how to continue.This is what I have:
log8^(2(x+2))=log16^(x-2)
2(x+2)log8= (x-2)log16
2xlog8 + 4log8 = xlog16 - 2log16
2xlog8 - xlog16 = -4log8 - 2log16
I don't know how to continue from here, can you please help me complete it, and tell me how you got from one step to the next. Thank you. Found 2 solutions by htmentor, MathTherapy:Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! Evaluate:
Use log base 2:
2(x+2)log2(8) = (x-2)log2(16)
(2x+4)3 = (x-2)4
Solving for x gives x = -10
You can put this solution on YOUR website!
Please help me solve this question
Evaluate:
I have started it but I'm not sure if I'm doing it right or how to continue.This is what I have:
log8^(2(x+2))=log16^(x-2)
2(x+2)log8= (x-2)log16
2xlog8 + 4log8 = xlog16 - 2log16
2xlog8 - xlog16 = -4log8 - 2log16
I don't know how to continue from here, can you please help me complete it, and tell me how you got from one step to the next. Thank you.
Convert to a similar base, which in this case is: base 2
With bases being similar, exponents are too. Therefore, 6(x + 2) = 4(x - 2)
6x + 12 = 4x - 8
6x - 4x = - 8 - 12
2x = - 20
, or
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
