SOLUTION: Please help me solve for R for this equation: {{{(R/(R+1)) + 2=(3R)/(R+2) }}}

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Question 68307: Please help me solve for R for this equation: %28R%2F%28R%2B1%29%29+%2B+2=%283R%29%2F%28R%2B2%29+
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve for R for this equation:
+%28R%2F%28R%2B1%29%29+%2B+2=%283R%29%2F%28R%2B2%29
:
Get rid of the denominators, multiply each term by (R+1)(R+2), results:
:
R(R+2) + 2(R+1)(R+2) = 3R(R+1)
:
R^2 + 2R + 2(R^2 + 3R + 2) = 3R^2 + 3R
:
R^2 + 2R + 2R^2 + 6R + 4 = 3R^2 + 3R
:
Group like terms on the left, -4 all alone on the right:
:
R^2 + 2R^2 - 3R^2 + 2R + 6R - 3R = -4
:
The R^2's cancel out leaving us with:
5R = -4
R = -4/5
:
It easier to check the solution if R=-.8:
Substitute -.8 for R:
:
+%28R%2F%28R%2B1%29%29+%2B+2=%283R%29%2F%28R%2B2%29
:
+%28-.8%2F%28-.8%2B1%29%29+%2B+2=%283%28-.8%29%29%2F%28-.8%2B2%29
:
+%28-.8%2F%28.2%29%29+%2B+2=%28-2.4%29%2F%281.2%29
:
- 4 + 2 = -2; checks our solution