SOLUTION: pleae help me solve this equation. Solve the equation for x over the interval [0,2pi) {{2sin^2x=squareroot(3)sinx

Algebra ->  Trigonometry-basics -> SOLUTION: pleae help me solve this equation. Solve the equation for x over the interval [0,2pi) {{2sin^2x=squareroot(3)sinx      Log On


   



Question 682761: pleae help me solve this equation. Solve the equation for x over the interval [0,2pi) {{2sin^2x=squareroot(3)sinx
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
2sinxsin^2x√3