SOLUTION: Please help to solve 3x^0 - 2(x-3^0)- the absolute value of -11 - 2(end absolute value) = 4x(2 - 5^0) - 7x

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Question 68276This question is from textbook An Incremental Development
: Please help to solve
3x^0 - 2(x-3^0)- the absolute value of -11 - 2(end absolute value) = 4x(2 - 5^0) - 7x This question is from textbook An Incremental Development

Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3x^0 - 2(x-3^0)- | -11 - 2| = 4x(2 - 5^0) - 7x
3*1 - 2(x-1)-13 = 4x(2-1)-7x
3 -2x+2-13 =4x-7x
-2x-8=-3x
x=8
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Cheers,
Stan H.

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
3x%5E0-2%28x-3%5E0%29-abs%28-11-2%29=4x%282-5%5E0%29-7x
3%281%29-2%28x-1%29-abs%28-12%29=4x%282-1%29-7x
3-2x%2B2-12=4x%281%29-7x
-2x-7=4x-7x
-2x-7=-3x
-2x%2B3x-7=-3x%2B3x
x-7=0
x-7%2B7=0%2B7
highlight%28x=7%29
Check by letting x=7 and see if both sides =.
3%287%29%5E0-2%287-3%5E0%29-abs%28-11-2%29=4%287%29%282-5%5E0%29-7%287%29
3%281%29-2%287-1%29-abs%28-12%29=28%282-1%29-49
3-2%286%29-%2812%29=28%281%29-49
3-12-12=28-49
-21=-21 We're right!!!
Happy Calculating!!!