SOLUTION: A boeing 747 flies the 3000 mile distance from Los Angeles to NEw York, with the tailwind, in 5 hours. The return trip, against the wind, takes 6 hours. Find the speed of the plane
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Question 682567: A boeing 747 flies the 3000 mile distance from Los Angeles to NEw York, with the tailwind, in 5 hours. The return trip, against the wind, takes 6 hours. Find the speed of the plane and the speed of the wind. Found 2 solutions by mananth, Alan3354:Answer by mananth(16946) (Show Source):
Plane speed =x mph
wind speed =y mph
against wind 6 hours
with wind 5 hours
Distance against 3000 miles distance with wind 3000 miles
t=d/r against wind -
3000 / ( x - y )= 6
6(x-y)=3000
6x-6y= 3000 ....................1
3000/(x-y)= 5
5(x+y) =3000
5x+5y =3000 ...............2
Multiply (1) by 5
Multiply (2) by 6
we get y
30 x + -30 y = 15000
30 x + 30 = 18000
60 x = 33000
/ 60
x = 550 mph
plug value of x in (1) y
6 x -6 y = 3000
3300 -6 -3300 = 3000
-6 y = 3000
-6 y = -300 mph
y = 50
Plane speed 550 mph
wind speed 50 mph
You can put this solution on YOUR website! A boeing 747 flies the 3000 mile distance from Los Angeles to NEw York, with the tailwind, in 5 hours. The return trip, against the wind, takes 6 hours. Find the speed of the plane and the speed of the wind.
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3000/5 = 600 mi/hr
3000/6 = 500 mi/hr
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The plane's speed is the average = 550 mi/hr
The windspeed is the difference = 50 mi/hr
