SOLUTION: Writing answer in y=mx+b form determine an equation of the line satisfying the stated conditions... through (1,-4)and parallel to the graph of 4x-2y=1. I do not know where to

Algebra ->  Linear-equations -> SOLUTION: Writing answer in y=mx+b form determine an equation of the line satisfying the stated conditions... through (1,-4)and parallel to the graph of 4x-2y=1. I do not know where to       Log On


   

Question 682300: Writing answer in y=mx+b form determine an equation of the line satisfying the stated conditions...
through (1,-4)and parallel to the graph of 4x-2y=1. I do not know where to start???
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
When an equation is in the form +y+=+m%2Ax+%2B+b+
+m+ = slope of the line
First put the given equation into this form.
+4x+-+2y+=+1+
Add +2y+ to both sides
+4x+=+2y+%2B+1+
Subtract +1+ from both sides
+2y+=+4x+-+1+
Divide both sides by +2+
+y+=+2x+-+1%2F2+
Now you know that +m+=+2+ for this line
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ANY line that is parallel to this line will have the same slope,
so at this point you have:
+y+=+2x+%2B+b+
All you need to find is +b+
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The line goes through the point ( 1,-4)
This is in the format (x,y)
I can now say
+-4+=+2%2A1+%2B+b+
+b+=+-4+-+2+
+b+=+-6+
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The solution is +y+=+2x+-+6+
Here is a plot of both lines:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+2x+-+1%2F2+%2C+2x+-+6+%29+