SOLUTION: 3x^2+3y^2-6y+12x=24 circle, ellipse, or hyperbola (3x^2+12x)+(3y^2-6y)=24 3(x^2+4x+4)+3(y^2-2y+1)=24+12+3

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 3x^2+3y^2-6y+12x=24 circle, ellipse, or hyperbola (3x^2+12x)+(3y^2-6y)=24 3(x^2+4x+4)+3(y^2-2y+1)=24+12+3       Log On


   

Question 682150: 3x^2+3y^2-6y+12x=24 circle, ellipse, or hyperbola
(3x^2+12x)+(3y^2-6y)=24
3(x^2+4x+4)+3(y^2-2y+1)=24+12+3
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2+3y^2-6y+12x=24 circle, ellipse, or hyperbola
(3x^2+12x)+(3y^2-6y)=24
3(x^2+4x+4)+3(y^2-2y+1)=24+12+3
3(x+2)^2+ 3(y-1)^2 = 39
(x+2)^2 + (y-2)^2 = 13
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Circle with center at (-2,2) and radius = sqrt(13)
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Cheers,
Stan H.