SOLUTION: Two girls, Jen and Amber, went for a walk. Jen begin walking 20 seconds earlier than amber. Jen walked at a speed of 4 feet per second and Amber walked at a speed of 6 feet per sec

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Question 682001: Two girls, Jen and Amber, went for a walk. Jen begin walking 20 seconds earlier than amber. Jen walked at a speed of 4 feet per second and Amber walked at a speed of 6 feet per second?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The question must be- when do they meet?
Jen's head start is:
+4%2A20+=+80+ ft
Let +d+ = the distance that Amber now has to
walk after Jen's head start
Let +t+ = the time for both after Jen's head start
------------
Jen's equation:
(1) +d+-+80+=+4t+
Amber's equation:
(2) +d+=+6t+
-------------
Substitute (2) into (1)
(1) +6t+-+80+=+4t+
(1) +2t+=+80+
(1) +t+=+40+
They will meet 40 sec after Amber starts
Jen walks for +20+%2B+40+=+60+, or 1 min
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check:
(2) +d+=+6t+
(2) +d+=+6%2A40+
(2) +d+=+240+ ft
and
(1) +d+-+80+=+4t+
(1) +d+-+80+=+4%2A40+
(1) +d+=+80+%2B+160+
(1) +d+=+240+ ft
OK