SOLUTION: find three consecutive numbers such that 3 times the first is equal to 8 more than the sum of the other two.

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Question 681956: find three consecutive numbers such that 3 times the first is equal to 8 more than the sum of the other two.
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x x+1 x+2
...
3x = x+1+x+2+8
3x = 2x + 11
3x - 2x = 11
x = 11
...
The numbers are
11, 12 and 13
.....................
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