SOLUTION: perpendicular to the line 8x-7y= 77 containing the points (7,-12)

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Question 681702: perpendicular to the line 8x-7y= 77 containing the points (7,-12)
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Starting with 8x-7y=77
Isolate y
8x-7y=77
8x-7y+7y = 77+7y
8x=77+7y
8x - 77 = 77 + 7y - 77
8x - 77 = 7y
...
7y = 8x - 77
y = %288%2F7%29x-11
...
The slope is 8%2F7
A perpendicular line will have a negative inverse/reciprocal slope of -7%2F8
...
Using point(7,-12)
y--12 = -7%2F8(x-7)
y+12 = %28-7%2F8%29x-%287%2F8%29%28-7%29
y = %28-7%2F8%29x+%2B+49%2F8+-+12
y = %28-7%2F8%29x+%2B+49%2F8+-+12%288%2F8%29
y = %28-7%2F8%29x+%2B+49%2F8+-+96%2F8
highlight_green%28y+=+%28-7%2F8%29x+-+47%2F8%29
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