SOLUTION: I am nowhere close to getting the answer can you please help me with this problem?
I have to solve the system by using the substitution or elimination methods.
x/3-y/5=4
3x/4+ 2
Algebra ->
Coordinate Systems and Linear Equations
-> SOLUTION: I am nowhere close to getting the answer can you please help me with this problem?
I have to solve the system by using the substitution or elimination methods.
x/3-y/5=4
3x/4+ 2
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Question 681668: I am nowhere close to getting the answer can you please help me with this problem?
I have to solve the system by using the substitution or elimination methods.
x/3-y/5=4
3x/4+ 2y/3=6 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! I have to solve the system by using the substitution or elimination methods.
x/3-y/5=4
3x/4+ 2y/3=6
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Get rid of fractions.
x/3 - y/5=4 times 15 --> 5x - 3y = 60
3x/4+ 2y/3=6 times 12 --> 9x + 8y = 72
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Get the same coefficient for either x or y. I'll do y.
5x - 3y = 60 times 8 --> 40x - 24y = 480
9x + 8y = 72 times 3 --> 27x + 24y = 216
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40x - 24y = 480
27x + 24y = 216
--------------- Add
67x = 696
x = 696/67
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Sub for x into any eqn to find y.
5x - 3y = 60
3480/67 - 60 = 3y
y = -180/67
