SOLUTION: Given that x+1 is a factor of P(x)=4x^3+4x^2-x-1, factor P(x) completely into linear factors. What are the zeros of P(x)?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Given that x+1 is a factor of P(x)=4x^3+4x^2-x-1, factor P(x) completely into linear factors. What are the zeros of P(x)?      Log On


   

Question 681659: Given that x+1 is a factor of P(x)=4x^3+4x^2-x-1, factor P(x) completely into linear factors. What are the zeros of P(x)?
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
P(x) = 4x%5E3%2B4x%5E2-x-1
Associative property of grouping
0= %284x%5E3%2B4x%5E2%29-%28x%2B1%29
0= 4x%5E2%28x%2B1%29-%28x%2B1%29
0= %284x%5E2-1%29%28x%2B1%29
highlight_green%280=%282x%2B1%29%282x-1%29%28x%2B1%29%29%29 ==> factored
...
zeros at 1%2F2, -1%2F2 and -1
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