SOLUTION: How would you solve log base 6 of 2x + log base 6 of (x-2) = 1?
Our teacher said the answer should be 3.
So far I condensed it to log base 6 of (2x(x-2)) or log base 6 of (2x^2
Algebra ->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: How would you solve log base 6 of 2x + log base 6 of (x-2) = 1?
Our teacher said the answer should be 3.
So far I condensed it to log base 6 of (2x(x-2)) or log base 6 of (2x^2
Log On
Question 681634: How would you solve log base 6 of 2x + log base 6 of (x-2) = 1?
Our teacher said the answer should be 3.
So far I condensed it to log base 6 of (2x(x-2)) or log base 6 of (2x^2-4x) = 1 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How would you solve log base 6 of 2x + log base 6 of (x-2) = 1?
Our teacher said the answer should be 3.
So far I condensed it to log base 6 of (2x(x-2)) or log base 6 of (2x^2-4x) = 1
=========================
log base 6 of (2x^2-4x) = 1
--> (2x^2-4x) = 6
x^2 - 2x -3 = 0
(x-3)*(x+1) = 0
x = -1 is rejected since won't work.
x = 3
