SOLUTION: What is the vertex and the axis of symmetry of the parabola y=x^2+5x-6

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Question 681141: What is the vertex and the axis of symmetry of the parabola y=x^2+5x-6
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the vertex and the axis of symmetry of the parabola
y=x^2+5x-6
complete the square:
y=(x^2+5x+25/4)-6-25/4
y=(x+5/2)^2-24/4-25/4
y=(x+5/2)^2-49/4
This is an equation of a parabola that opens upwards.
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex
For given equation: y=(x+5/2)^2-49/4
vertex: (-5/2,-49/4)
axis of symmetry: x=-5/2
see graph below:
+graph%28+300%2C+300%2C+-10%2C+10%2C+-20%2C+10%2C%28x%2B5%2F2%29%5E2-49%2F4%29+