SOLUTION: Solve {{{4^x=2}}} There are a couple of ways to solve this. You can use logs, however, in this case it is easiest to equate the bases. {{{4^x=2}}} {{{(2^2)^x=2}}} {{{2^(2x

Algebra ->  Test -> SOLUTION: Solve {{{4^x=2}}} There are a couple of ways to solve this. You can use logs, however, in this case it is easiest to equate the bases. {{{4^x=2}}} {{{(2^2)^x=2}}} {{{2^(2x      Log On


   

Question 681001: Solve 4%5Ex=2
There are a couple of ways to solve this. You can use logs, however, in this case it is easiest to equate the bases.
4%5Ex=2
%282%5E2%29%5Ex=2
2%5E%282x%29=2%5E1
once the bases are the same, then the exponents are equal and you can solve for x.
2x=1
2x%2F2=1%2F2
x=1%2F2
Hope that helped. Happy Calculating!
Answer by funmath(2933) About Me  (Show Source):