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Question 680785: there are two numbers. twice the first number plus three times the second number is 72. the difference of the two numbers is 16. what are the numbers?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! there are two numbers.
x & y
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twice the first number plus three times the second number is 72.
2x + 3y = 72
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the difference of the two numbers is 16.
x - y = 16
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Multiply the above equation by 3, add to the 1st equation
2x + 3y = 72
3x - 3y = 48
-------------adding eliminates y, find x
5x = 120
x = 120/5
x = 24
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I'll let you find y, check solutions in both equations
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