SOLUTION: y+3/y-3=y-4/y-5+1
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Algebra: Radicals -- complicated equations involving roots
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Question 680571
:
y+3/y-3=y-4/y-5+1
Answer by
stanbon(75887)
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y+3/y-3=y-4/y-5+1
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(y+3)/(y-3) = (y-4)/(y-5) + 1
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Multiply thru by (y-3)(y-5) to get:
(y+3)(y-5) = (y-4)(y-3) + (y-3)(y-5)
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y^2 - 2y - 15 = y^2-7y+12 + y^2-8y+15
=====
y^2 -2y-15 = 2y^2-15y + 27
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y^2 - 13y +42 = 0
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Factor:(y-6)(y-7) = 0
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y = 6 or y = 7
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Cheers,
Stan H.