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Question 68057This question is from textbook Algebra
: Hi I need help with this problem. I tried following the examples from the book but I just couldn't get the right answer.
Luis & Julia have the same number of coins. Luis has only dimes & Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
This question is from textbook Algebra
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Luis & Julia have the same number of coins. Luis has only dimes & Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
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Luis has "x" dimes that are worth 10x cents
Julia has "x" quarters that are worth 25x cents
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INEQUALIty:
Julia value - 180 cents = Luis value
25x-180 = 10x
15x=180
x=12 (number of dimes Luis has)
x=12 (number of quarters Julia has)
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Cheers,
Staan H.
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