SOLUTION: Can you tell me if I have done this correctly? For the function f(x)=(3-4x)^2, find f^-1. Determine whether f^-1 is a function.
sq rt.y=3-4x
sq rt y^-3=-4x
x=(sq rt y^-3)/-4
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-> SOLUTION: Can you tell me if I have done this correctly? For the function f(x)=(3-4x)^2, find f^-1. Determine whether f^-1 is a function.
sq rt.y=3-4x
sq rt y^-3=-4x
x=(sq rt y^-3)/-4
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Question 680309: Can you tell me if I have done this correctly? For the function f(x)=(3-4x)^2, find f^-1. Determine whether f^-1 is a function.
sq rt.y=3-4x
sq rt y^-3=-4x
x=(sq rt y^-3)/-4
f^-1(x)=sq rt y^-3/-4 and it is not a function. Thanks Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Can you tell me if I have done this correctly? For the function f(x)=(3-4x)^2, find f^-1. Determine whether f^-1 is a function.
sq rt.y=3-4x
sq rt y^-3=-4x ****** The ^ is unnecessary and confusing ****
x=(sq rt y^-3)/-4
f^-1(x)=sq rt y^-3/-4 and it is not a function. Thanks
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f(x)=(3-4x)^2
y = (3-4x)^2
--> x = (3-4y)^2
3-4y = sqrt(x)
y = (3 - sqrt(x))/4 Same as your answer.
Not a function.
