Question 680053: An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
csc 4θ − 2 = 0
(a) Find all solutions of the equation.
(b) Find the solutions in the interval [0, 2π).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
csc 4θ − 2 = 0
(a) Find all solutions of the equation.
(b) Find the solutions in the interval [0, 2π).
**
(a) All solutions
csc 4x-2=0
csc 4x=2
1/cos 4x=2
cos 4x=1/2
4x=π/6+2πk, 5π/6+2πk, k=integer
x=π/24+2πk, 5π/24+2πk, k=integer
..
(b) Interval [0,2π]
4x=π/6, 5π/6 (In QI and QII where sin>0)
x=π/24, 5π/24
|
|
|
