SOLUTION: I need help in this percentage problem. Thank you.
How much pure acid should be mixed with 6 gallons of a 50 % acid solution in order to get an 80 % acid solution?
A) 15 gal
Question 679975: I need help in this percentage problem. Thank you.
How much pure acid should be mixed with 6 gallons of a 50 % acid solution in order to get an 80 % acid solution?
A) 15 gal
B) 3 gal
C) 9 gal
D) 24 gal Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How much pure acid should be mixed with 6 gallons of a 50 % acid solution in order to get an 80 % acid solution?
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Equation:
acid + acid = acid
0.50*6 + 1.00x = 0.80(6+x)
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Multiply thru by 100 to get:
50*6 + 100x = 80*6 + 80x
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20x = 30*6
x = 9 gallons (amt. of pure acid to be added)
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Cheers,
Stan H.
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A) 15 gal
B) 3 gal
C) 9 gal
D) 24 gal
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