SOLUTION: Find the distance between (-3, -2) and (1, 4) A) sqrt 10 B) 27 C) 2 sqrt 5 D) 2 sqrt 13 Can anyone help me understand this problem? Thank you so very much!!

Algebra ->  Square-cubic-other-roots -> SOLUTION: Find the distance between (-3, -2) and (1, 4) A) sqrt 10 B) 27 C) 2 sqrt 5 D) 2 sqrt 13 Can anyone help me understand this problem? Thank you so very much!!      Log On


   

Question 67968: Find the distance between (-3, -2) and (1, 4)
A) sqrt 10
B) 27
C) 2 sqrt 5
D) 2 sqrt 13
Can anyone help me understand this problem? Thank you so very much!!
Found 2 solutions by Earlsdon, venugopalramana:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You can use the distance formula: d+=+sqrt%28%28x2-x1%29%5E2+%2B+%28y2-y1%29%5E2%29 which is derived from the Pythagorean theorem.
(x1, y1) = (-3, -2) and (x2, y2) = (1, 4) Making the appropriate substitutions:
d+=+sqrt%28%281-%28-3%29%29%5E2+%2B+%284-%28-2%29%29%5E2%29
d+=+sqrt%284%5E2+%2B+6%5E2%29
d+=+sqrt%2816%2B36%29
d+=+sqrt%2852%29
d+=+sqrt%284%2A13%29
d+=+2sqrt%2813%29

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
Find the distance between (-3, -2)..CALL IT P SAY WITH (X1,Y1) COORDINATES
SO X1=-3...Y1=-2
and
(1, 4)...CALL IT Q SAY WITH (X2,Y2) COORDINATES.SO X2=1...Y2=4
DISTANCE (D)BETWEEN 2 POINTS PQ IS GIVEN BY FORMULA
D=SQRT[(X2-X1)^2+(Y2-Y1)^2]=SQRT[(1+3)^2+(4+2)^2]=SQRT[4^2+6^2]=SQRT(16+36)
=SQRT(52)=SQRT(4*13)=[SQRT(4)]=2*SQRT(13)............D IS THE ANSWER

A) sqrt 10
B) 27
C) 2 sqrt 5
D) 2 sqrt 13
Can anyone help me understand this problem? Thank you so very much!!