SOLUTION: twice the first of three consecutive even integers minus the third equals 36. Find the three integers.

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Question 679678: twice the first of three consecutive even integers minus the third equals 36. Find the three integers.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
twice the first of three consecutive even integers minus the third equals 36. Find the three integers.
1st: 2x-2
2nd: 2x
3rd: 2x+2
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Equation:
2(2x-2)-(2x+2)= 36
4x-4-2x-2 = 36
2x = 42
x = 21
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1st: 2*21-2 = 40
2nd: 42
3rd: 44
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Cheers,
Stan H.
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