Question 679516: Please help me solve the parabola, ((( y=-1/16x^2 ))).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! solve the parabola, ((( y=-1/16x^2 ))).
This is an equation of a parabola that opens downwards.
Its standard form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
When A<0, parabola opens downwards, when A>0, parabola opens upwards.
For given equation: y=-1/16x^2
A=-1/16
vertex: (0,0)
axis of symmetry: x=0
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