It is already solved for in terms of . You could solve it for in terms of by adding 8 to both sides and multiplying both sides by 1/7 -- although generally speaking that would be a very odd thing to do indeed.
Other than that, the equation has a solution set that consists of an infinite number of ordered pairs of the form where
You have to be more specific about what you want if you are really interested in getting help here.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
