SOLUTION: 3log2 x=1+log2 32
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Question 67909
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3log2 x=1+log2 32
Answer by
stanbon(75887)
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3log2 x=1+log2 32
---------
log(base2)x^3 = 1+log(base2)32
log(base2)[x^3/32] = 1
x^3/32 = 2^1
x^3=64
x=4
Cheers,
Stan H.