SOLUTION: Question: Write an equation in slope-intercept form of the line satisfying the given conditions... Perpendicular to the line y=2x+3; containing the point (-2,-4). My answer wa

Algebra ->  Linear-equations -> SOLUTION: Question: Write an equation in slope-intercept form of the line satisfying the given conditions... Perpendicular to the line y=2x+3; containing the point (-2,-4). My answer wa      Log On


   

Question 678815: Question:
Write an equation in slope-intercept form of the line satisfying the given conditions...
Perpendicular to the line y=2x+3; containing the point (-2,-4).
My answer was wrong, but here it is: y= -1/2x-4
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Using y=2x+3, the slope is 2
...
A perpendicular line will have the negative inverse (reciporcal) slope of -1%2F2
...
Using the point (-2,-4) and the determined slope, plug into the point-slope formula.
y - -4 = -1%2F2(x--2)
y + 4 = -1%2F2(x+2)
y + 4 = %28-1%2F2%29x+-+%281%2F2%29%282%29
...
y = %28-1%2F2%29x+-+1-4
...
highlight_green%28y=%28-1%2F2%29x-5%29
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