Question 678697: Exponential growth problem using the formula: N= No(R)^t/d
N is the current amount, No is the initial amount, R is the rate, t is the time, d is the number of days/months/years
The population of a city was estimated to be 125000 in 1930 and 500000 in 1998.
a) Estimate the population of the city in 2020.
b) if the population continues to grow at the same rate, when will the population reach 1 million?
Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! If we know that grows exponentially,
we know the "initial" value of at some point we take as starting point,
and we know that grew by a factor of over a period of days/months/years (or whatever unit of time),

that gives the value of at a time days/months/years (or whatever unit of time we were using) after our starting point.
THE PROBLEM SET-UP:
Here we define
start = year 1930
we measure time in years
for 1930
for 1998
for 2020
years (between 1930 and 1998)
is the growth factor over 68 years
(the population quadrupled in the 68 years between 1930 and 1998).
is our starting population
, with   
PART a:
In the year 2020, for , the population is


PART b:
To calculate when the population will be one million.

Taking logs of both sides

From there we get <--> ,
which corresponds to year 
I really did not bother with the calculation.
It was just mental math.
I knew (from way before) that the population had quadrupled in 68 years.
That meant that it doubled every 34 years,
so that in years it would double twice,
and would end up multiplying times 2 twice to quadruple.
Then, being 500,000 in 1998,
it needed just another 32 years to double again, and reach one million.
|
|
|