SOLUTION: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 474 feet, find the width and the length. This real-world pro

Algebra ->  Length-and-distance -> SOLUTION: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 474 feet, find the width and the length. This real-world pro      Log On


   



Question 678479: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 474 feet, find the width and the length.
This real-world problem can be solved using a linear equation.
First express the length L of the rectangle in terms of the width W. We are given that the length is 3 feet less than twice the width.

Answer by rm29924(97) About Me  (Show Source):
You can put this solution on YOUR website!
perimeter of a rectangle=
perimeter=2(length)+2(width)
perimeter=474 feet
let W=width
the length=2W-3
W+2W-3=474
3w-3=474
3w=477
w=159
length is 2W-3
2(159)-3
318-3
315
the width is 159 ft and the length is 315 ft