Question 678340: three times the sum of a number and 4 is 8 less than one-half the number. write and solve an equation to find the number. Found 2 solutions by ReadingBoosters, rm29924:Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website! 3(n+4) = n-8
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multiply the entire equation by 2 to be rid of the fraction
2[3(n+4)] = 2()n-2(8)
6(n+4) = n - 16
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distribute the 6
6n + 24 = n - 16
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Group the n variable on the left side alone
6n - n = -16 - 24
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Combine like terms
5n = -40
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Divide both sides by 5 to isolate n
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You can put this solution on YOUR website! Let X = a number
three times the sum of a number and 4
the sum of a number and 4 means you add them
x+4
three times means multiply by 3
3(x+4)
8 less than one-half the number
one half the number is 1/2X
8 less means subtract 8
1/2x-8
is means equals so set those equal to each other
3(x+4)=1/2x-8
3x+12=1/2x-8
subtract 3x from both sides
12=-2.5x-8
add 8 to both sides
20=-2.5x
divide both sides by 2.5
x= - 8
plug it back into the equation to check work
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