SOLUTION: someone please explain how to do this please!!!! Given the mean is 70 and the standard deviation is 8. Find the largest fraction of the numbers that could meet less than 50 o

Algebra ->  Probability-and-statistics -> SOLUTION: someone please explain how to do this please!!!! Given the mean is 70 and the standard deviation is 8. Find the largest fraction of the numbers that could meet less than 50 o      Log On


   



Question 678253: someone please explain how to do this please!!!!

Given the mean is 70 and the standard deviation is 8. Find the largest fraction of the numbers that could meet less than 50 or more than 90.
Note: If your answer is

to give it as a fraction, you will need to type it in as 3/4
Hint: Use Chebyshev's Theorem.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given the mean is 70 and the standard deviation is 8. Find the largest fraction of the numbers that could meet less than 50 or more than 90.
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z(50) = (50-70)/8 = -20/8 = -5/2
z(90) = (90-70)/8 = +5/2
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Using Chebyshev:
P(50<= x <=90) is at least (1-(2/5)^2) = 0.84 = 84%
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Cheers,
Stan H.
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