SOLUTION: Say that a town has 1,000 residents,of whom 60% are women and 40% are men.Of the women,40% wear one earring.Half of the rest wear 2 earrings,and half wear none.Of the men,60% wear

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Say that a town has 1,000 residents,of whom 60% are women and 40% are men.Of the women,40% wear one earring.Half of the rest wear 2 earrings,and half wear none.Of the men,60% wear       Log On


   

Question 67800: Say that a town has 1,000 residents,of whom 60% are women and 40% are men.Of the women,40% wear one earring.Half of the rest wear 2 earrings,and half wear none.Of the men,60% wear one earring.Half of the rest wear 2 earrings,and half wear none.How many earrings are worn in all?
Answer by wgunther(43) About Me  (Show Source):
You can put this solution on YOUR website!
This problem has ties in things like the law of total probability and inutuitivly makes sense. 60% of the town is women, so that's 600 women. 40% wear one earing and half of the rest wear two. The rest is 60%, half of it is 30%. So,
%0D%0A600%2A%28.4%2B2%2A.3%29%0D%0A
This is the number of earring worn by women. It's 2*.3 because 30% wears two earrings. Clearly then there are 400 men in the town. 60% wear one earring and half ot the rest wear two. The rest is 40%, half is 20%. So,
%0D%0A400%2A%28.4%2B2%2A.2%29%0D%0A
This is the number of earrings worn by men.