SOLUTION: The area of a rectangular carpet is 72 square feet. The carpet's length is (x + 4) and the carpet's width is (5x + 2) feet. Find the dimensions of the carpet

Algebra ->  Rectangles -> SOLUTION: The area of a rectangular carpet is 72 square feet. The carpet's length is (x + 4) and the carpet's width is (5x + 2) feet. Find the dimensions of the carpet      Log On


   

Question 677979: The area of a rectangular carpet is 72 square feet. The carpet's length is (x + 4) and the carpet's width is (5x + 2) feet. Find the dimensions of the carpet
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
a = lw = 72
l = x+4
w = 5x+2
...
(x+4)(5x+2) = 72
5x%5E2+%2B+2x+%2B+20x+%2B+8+=+72
5x%5E2+%2B+22x+-+64+=+0
...
Quadratic Equation
x = %28-22+%2B-+sqrt%2822%5E2-4%285%29%28-64%29%29%29%2F2%285%29}
...
x = %28-22+%2B-+sqrt%28484%2B1280%29%29%2F10
...
x = %28-22+%2B-+sqrt%281764%29%29%2F10
...
x = %28-22+%2B-42%29%2F10
...
x = %28-22%2B42%29%2F10+=+20%2F10+=+2
Or
x = %28-22-42%29%2F10+=+-64%2F10+=+-6.4 --> don't use the negative because dimensions cannot be negative.
...
...
l = x+4 = 2+4 = highlight_green%28l=6%29 ft
w = 5x+2 = 5(2)+2 = 10+2 = highlight_green%28w=12%29 ft
...
Check 6*12 = 72
............
Delighted to help.
-Reading Boosters
Website: www.MyHomeworkAnswers.com
Wanting for others what we want for ourselves.