SOLUTION: Find all real numbers in the interval [0,2pi) that satisfy the equation. Use radian measure. 3sin 2x = sin x
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Question 677946: Find all real numbers in the interval [0,2pi) that satisfy the equation. Use radian measure. 3sin 2x = sin x Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find all real numbers in the interval [0,2pi) that satisfy the equation. Use radian measure.
3sin 2x = sin x
3(2sinxcosx)=sinx
6cosx=1
cosx=1/6
using calculator set to radians:
x≈1.40, 4.88 (in quadrants I and IV where cos>0)
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