SOLUTION: Solve for x in [0,2pi]: cos x - sin x = -1
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Question 677926
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Solve for x in [0,2pi]:
cos x - sin x = -1
Answer by
lwsshak3(11628)
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Solve for x in [0,2pi]:
cos x - sin x = -1
square both sides
cos^2x-2sinxcosx+sin^2x=1
-sin(2x)+1=1
-sin(2x)=0
2x=0,π
x=0, π/2