SOLUTION: The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as the population parameters). Suppose 36 pro golfers

Click here to see ALL problems on Probability-and-statistics

Question 677756: The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as the population parameters). Suppose 36 pro golfers played the course today. Find the probability that the average score of the 36 golfers was less than 69. (Hint: think of this in terms of a sampling distribution with sample size 36)
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as the population parameters). Suppose 36 pro golfers played the course today. Find the probability that the average score of the 36 golfers was less than 69. (Hint: think of this in terms of a sampling distribution with sample size 36)
-----
The stardard deviation for all groups of size 36 is 3/sqrt(36) = 1/2
-------
z(69) = (69-70)/(1/2) = -1/(1/2) = -2
-------
P(x-bar < 69) = P(z < -2) = normalcdf(-100,-2) = 0.0228
=============
Cheers,
Stan H.
===============