SOLUTION: In the parallelogram ABCD, AB=3 cm and AD=2cm. The distance between AB and CD is 1cm. Find the distance between AD and BC.
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Question 677657: In the parallelogram ABCD, AB=3 cm and AD=2cm. The distance between AB and CD is 1cm. Find the distance between AD and BC. Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! the area of a parallelogram is base * height
so taking AB as base area of parallelogram= AB*distance betn AB & CD=3*1=3....1
now taking AD as base area of parallelogram= AD*distance betn AD & BC
=2*distance betn AD & BC................2
equating the above two eqns
so 2*distance betn AD & BC=3
or distance betn AD & BC=3/2
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