SOLUTION: A father is 26 years older than his daughter. In four years he will be 2 more than 5 times her age. Find each of their current ages.

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Question 677441: A father is 26 years older than his daughter. In four years he will be 2 more than 5 times her age. Find each of their current ages.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = the Daughter's age now
+d+%2B+26+ is the Father's age now
+d+%2B+4+ = the Daughter's age in +4+ years
+5%2A%28+d+%2B+4+%29+%2B+2+ = the Father's age in +4+ years
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The thing about ages is that the difference between
their ages will always remain the same, +26+ years, so
+5%2A%28+d+%2B+4+%29+%2B+2+-+%28+d+%2B+4+%29+=+26+
+5d+%2B+20+%2B+2+-+d+-+4+=+26+
+4d+=+26+-+20+-+2+%2B+4+
+4d+=+8+
+d+=+2+
+d+%2B+26+=+2+%2B+26+
+d+%2B+26+=+28+
The Daughter's age is 2 now
The Father's age is 28 now
check:
+5%2A%28+d+%2B+4+%29+%2B+2+-+%28+d+%2B+4+%29+=+26+
+5%2A%28+2+%2B+4+%29+%2B+2+-+%28+2+%2B+4+%29+=+26+
+5%2A6+%2B+2+-+6+=+26+
+32+-+6+=+26+
+32+=+32+
OK