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| Question 677417:  There are four consecutive integers.  Their sum is 100 decreased by twice the difference between the greatest and twice the least.
 Answer by ReadingBoosters(3246)
      (Show Source): 
You can put this solution on YOUR website! Establish variables x x+1 x+2 x+3
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 x+x+1+x+2+x+3=100-2((x+3)-2x)
 4x + 6 = 100 - 2(x+3-2x)
 Distribute the 2
 4x + 6 = 100 - 2x - 2(3) - 2(-2x)
 4x + 6 = 100 - 2x - 6 + 4x
 4x - 4x + 2x = 100 - 6 - 6
 2x = 88
 x = 44
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 Integers are 44, 45, 46, 47
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