SOLUTION: 2k^2+16k=-12 what i have already k^2+8k=-6 (k^2+8k+16)=-6+16 square root of (x+4)^2 square roof of (10) what is the vertex? solve by compleating the square

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 2k^2+16k=-12 what i have already k^2+8k=-6 (k^2+8k+16)=-6+16 square root of (x+4)^2 square roof of (10) what is the vertex? solve by compleating the square       Log On


   

Question 677395: 2k^2+16k=-12
what i have already
k^2+8k=-6
(k^2+8k+16)=-6+16
square root of (x+4)^2 square roof of (10) what is the vertex? solve by compleating the square
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
y = 2k%5E2%2B16k%2B12
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y - 12 = 2k%5E2%2B16k
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y - 12 = 2(k%5E2%2B8k)
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y - 12 + 2(16) = 2(k%5E2%2B8k%2B16)
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y - 12 + 32 = 2%28x%2B4%29%5E2
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y + 20 = 2%28x%2B4%29%5E2
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y = 2%28x-+-4%29%5E2 + -20
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Using y=a%28x-h%29%5E2 + k
where vertex is (h,k)
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Vertex is: (-4,-20)
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graph%28300%2C200%2C-10%2C10%2C-25%2C5%2C2x%5E2%2B16x%2B12%29
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