SOLUTION: find two consecutive intergers such that the sum of five times the smaller and three times the larger is 67.

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Question 677179: find two consecutive intergers such that the sum of five times the smaller and three times the larger is 67.
Found 2 solutions by fcabanski, ReadingBoosters:
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Call these integers x and y where y is the larger so y=x+1. Three times the larger is 3y. Five times the smaller is 5x. Their sum is 3y + 5x and it equals 67.


We now have two equations and two unknowns.


y=x+1 and 3y + 5x = 67.


Substitute x+1 for y in the second equation and solve for x. 3(x+1) + 5x =67---> 3x + 3 +5x = 67 ---> 8x = 64 ---> x=8.


y=x+1=9. The integers are 8 and 9.

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Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x x+1
...
5x + 3(x+1) = 67
5x + 3x + 3 = 67
8x + 3 = 67
8x = 67 - 3
8x = 64
x = 8
...
Integers are 8 and 9
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