SOLUTION: the sum of two numbers is 18 seven times the smaller number minus twice the larger one is 36 what are the two numbers

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Question 676824: the sum of two numbers is 18 seven times the smaller number minus twice the larger one is 36 what are the two numbers
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x = one number
y = another number
...
x+y=18
7y-2x = 36
...
Rearrange the first equation as x = 18-y
Substitute into the second equation
7y - 2(18-y) = 36
Distribute the 2
7y - 2(18) - 2(-y) = 36
7y - 36 + 2y = 36
Isolate the y variable
9y = 36 + 36
9y = 72
Divide both sides by 9
highlight_green%28y=8%29
x = 18-8 = highlight_green%28x=10%29
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-Reading Boosters
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