SOLUTION: sally lives in chicago rocky lives in ohio 315 kilometers apart sally rides her motorcycle at 115 km/hr rocky can ride his at 60km/hr they leave at same time in how hours will they

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: sally lives in chicago rocky lives in ohio 315 kilometers apart sally rides her motorcycle at 115 km/hr rocky can ride his at 60km/hr they leave at same time in how hours will they      Log On

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Question 676634: sally lives in chicago rocky lives in ohio 315 kilometers apart sally rides her motorcycle at 115 km/hr rocky can ride his at 60km/hr they leave at same time in how hours will they meet
Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
They meet when they are both the same distance from Chicago. Let t=time it takes for that to happen
distance that Rocky is from Chi in t hours=315-60t
distance that Sally is from Chi in t hours= 115t
Soooooo
315-60t=115t
175t=315
t=1.8 hrs
CK
in 1.8 hrs, Rocky has traveled 60*1.8=108 mi and is 315-108=207 mi from Chicago
in 1.8 hrs, Sally has traveled 115*1.8 mi=207 mi and is 207 mi from Chicago
Hope this helps---ptaylor