SOLUTION: ok its more like factoring... but i totally forgot how to factor. ok so heres the problem: 6x^2-7x+2.... and i tried it and i got something like (3x+2)(2x-3) but ya thats not r

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: ok its more like factoring... but i totally forgot how to factor. ok so heres the problem: 6x^2-7x+2.... and i tried it and i got something like (3x+2)(2x-3) but ya thats not r      Log On


   

Question 67660: ok its more like factoring... but i totally forgot how to factor. ok so heres the problem:
6x^2-7x+2....
and i tried it and i got something like (3x+2)(2x-3) but ya thats not right because when i used FOIL it doesnt come out to what it should be... please help?!
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2-7x+2
(3x-2)(2x-1)
now FOIL
3x*2x=6x^2
3x*-1=-3x
-2*2x=-4x
-2*-1=2
so we have 6x^2-7x+2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2-7x+2....
Here's one method; it's called the AC method.
a=6, b=-7, c=2
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Find two numbers whose
product is AC = 12
and whose
sum is sum is B = -7
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The numbers are -3 and -4
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Replace the middle term of the problem with -3x-4x to get:
6x^2-3x-4x+2
----------------
Now factor the 1st terms and the last two terms separately to get:
3x(2x-1)-2(2x-1)
Then factor out the common factor to end the process:
(2x-1)(3x-2)
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Comment:
This may look complicated but it beas guessing.
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Cheers,
Stan H.